1. A function f(x) is defined as being equal to 1+x when x0, to x when 0<x<1, to 2x when 1x2, and to 3xx2 when x>2. Discuss the continuity of f(x) and the existence and continuity of f(x) for x=0, x=1, and x=2.

 

2. Denoting a, ax+b, ax2+2bx+c, … by u0, u1, u2, …, show that u02u33u0u1u2+2u13 and u0u44u1u3+3u22 are independent of x.

 

3. If a0, a1, …, a2n are constants and Ur=(a0,a1,,ar|x,1)r, then U0U2n2nU1U2n1+2n(2n1)12U2U2n2+U2nU0 is independent of x.

[Differentiate and use the relation Ur=rUr1.]

 

4. The first three derivatives of the function arcsin(μsinx)x, where μ>1, are positive when 0x12π.

 

5. The constituents of a determinant are functions of x. Show that its differential coefficient is the sum of the determinants formed by differentiating the constituents of one row only, leaving the rest unaltered.

 

6. If f1, f2, f3, f4 are polynomials of degree not greater than 4, then |f1f2f3f4f1f2f3f4f1f2f3f4f1f2f3f4| is also a polynomial of degree not greater than 4. [Differentiate five times, using the result of Ex. 5, and rejecting vanishing determinants.]

 

7. If y3+3yx+2x3=0 then x2(1+x3)y32xy+y=0.

 

8. Verify that the differential equation y=ϕ{ψ(y1)}+ϕ{xψ(y1)}, where y1 is the derivative of y, and ψ is the function inverse to ϕ, is satisfied by y=ϕ(c)+ϕ(xc) or by y=2ϕ(12x).

 

9. Verify that the differential equation y={x/ψ(y1)}ϕ{ψ(y1)}, where the notation is the same as that of Ex. 8, is satisfied by y=cϕ(x/c) or by y=βx, where β=ϕ(α)/α and α is any root of the equation ϕ(α)αϕ(α)=0.

 

10. If ax+by+c=0 then y2=0 (suffixes denoting differentiations with respect to x). We may express this by saying that the general differential equation of all straight lines is y2=0. Find the general differential equations of (i) all circles with their centres on the axis of x, (ii) all parabolas with their axes along the axis of x, (iii) all parabolas with their axes parallel to the axis of y, (iv) all circles, (v) all parabolas, (vi) all conics.

[The equations are (i) 1+y12+yy2=0, (ii) y12+yy2=0, (iii) y3=0, (iv) (1+y12)y3=3y1y22, (v) 5y32=3y2y4, (vi) 9y22y545y2y3y4+40y33=0. In each case we have only to write down the general equation of the curves in question, and differentiate until we have enough equations to eliminate all the arbitrary constants.]

 

11. Show that the general differential equations of all parabolas and of all conics are respectively Dx2(y22/3)=0,Dx3(y22/3)=0.

[The equation of a conic may be put in the form y=ax+b±px2+2qx+r. From this we deduce y2=±(prq2)/(px2+2qx+r)3/2. If the conic is a parabola then p=0.]

 

12. Denoting dydx, 12!d2ydx2, 13!d3ydx3, 14!d4ydx4, … by t, a, b, c, … and dxdy, 12!d2xdy2, 13!d3xdy3, 14!d4xdy4, … by τ, α, β, γ, …, show that 4ac5b2=(4αγ5β2)/τ8,bta2=(βτα2)/τ6. Establish similar formulae for the functions a2d3abc2b3, (1+t2)b2a2t, 2ct5ab.

 

13. Prove that, if yk is the kth derivative of y=sin(narcsinx), then (1x2)yk+2(2k+1)xyk+1+(n2k2)yk=0.

[Prove first when k=0, and differentiate k times by Leibniz’ Theorem.]

 

14. Prove the formula vDxnu=Dxn(uv)nDxn1(uDxv)+n(n1)12Dxn2(uDx2v) where n is any positive integer. [Use the method of induction.]

 

15. A curve is given by x=a(2cost+cos2t),y=a(2sintsin2t).

Prove (i) that the equations of the tangent and normal, at the point P whose parameter is t, are xsin12t+ycos12t=asin32t,xcos12tysin12t=3acos32t; (ii) that the tangent at P meets the curve in the points Q, R whose parameters are 12t and π12t; (iii) that QR=4a; (iv) that the tangents at Q and R are at right angles and intersect on the circle x2+y2=a2; (v) that the normals at P, Q, and R are concurrent and intersect on the circle x2+y2=9a2; (vi) that the equation of the curve is (x2+y2+12ax+9a2)2=4a(2x+3a)3.

Sketch the form of the curve.

 

16. Show that the equations which define the curve of Ex. 15 may be replaced by ξ/a=2u+(1/u2), η/a=(2/u)+u2, where ξ=x+yi, η=xyi, u=Cist. Show that the tangent and normal, at the point defined by u, are u2ξuη=a(u31),u2ξ+uη=3a(u3+1), and deduce the properties (ii)–(v) of Ex. 15.

 

17. Show that the condition that x4+4px34qx1=0 should have equal roots may be expressed in the form (p+q)2/3(pq)2/3=1.

 

18. The roots of a cubic f(x)=0 are α, β, γ in ascending order of magnitude. Show that if [α,β] and [β,γ] are each divided into six equal sub-intervals, then a root of f(x)=0 will fall in the fourth interval from β on each side. What will be the nature of the cubic in the two cases when a root of f(x)=0 falls at a point of division?

 

19. Investigate the maxima and minima of f(x), and the real roots of f(x)=0, f(x) being either of the functions xsinxtanα(1cosx),xsinx(αsinα)tan12α(cosαcosx), and α an angle between 0 and π. Show that in the first case the condition for a double root is that tanαα should be a multiple of π.

 

20. Show that by choice of the ratio λ:μ we can make the roots of λ(ax2+bx+c)+μ(ax2+bx+c)=0 real and having a difference of any magnitude, unless the roots of the two quadratics are all real and interlace; and that in the excepted case the roots are always real, but there is a lower limit for the magnitude of their difference.

[Consider the form of the graph of the function (ax2+bx+c)/(ax2+bx+c): cf. Exs. XLVI. 12 et seq.]

 

21. Prove that π<sinπxx(1x)4 when 0<x<1, and draw the graph of the function.

 

22. Draw the graph of the function πcotπx1x1x1.

 

23. Sketch the general form of the graph of y, given that dydx=(6x2+x1)(x1)2(x+1)3x2.

 

24. A sheet of paper is folded over so that one corner just reaches the opposite side. Show how the paper must be folded to make the length of the crease a maximum.

 

25. The greatest acute angle at which the ellipse (x2/a2)+(y2/b2)=1 can be cut by a concentric circle is arctan{(a2b2)/2ab}.

 

26. In a triangle the area Δ and the semi-perimeter s are fixed. Show that any maximum or minimum of one of the sides is a root of the equation s(xs)x2+4Δ2=0. Discuss the reality of the roots of this equation, and whether they correspond to maxima or minima.

[The equations a+b+c=2s, s(sa)(sb)(sc)=Δ2 determine a and b as functions of c. Differentiate with respect to c, and suppose that da/dc=0. It will be found that b=c, sb=sc=12a, from which we deduce that s(as)a2+4Δ2=0.

This equation has three real roots if s4>27Δ2, and one in the contrary case. In an equilateral triangle (the triangle of minimum perimeter for a given area) s4=27Δ2; thus it is impossible that s4<27Δ2. Hence the equation in a has three real roots, and, since their sum is positive and their product negative, two roots are positive and the third negative. Of the two positive roots one corresponds to a maximum and one to a minimum.]

 

27. The area of the greatest equilateral triangle which can be drawn with its sides passing through three given points A, B, C is 2Δ+a2+b2+c223, a, b, c being the sides and Δ the area of ABC.

 

28. If Δ, Δ are the areas of the two maximum isosceles triangles which can be described with their vertices at the origin and their base angles on the cardioid r=a(1+cosθ), then 256ΔΔ=25a45.

 

29. Find the limiting values which (x24y+8)/(y26x+3) approaches as the point (x,y) on the curve x2y4x24xy+y2+16x2y7=0 approaches the position (2,3).

[If we take (2,3) as a new origin, the equation of the curve becomes ξ2ηξ2+η2=0, and the function given becomes (ξ2+4ξ4η)/(η2+6η6ξ). If we put η=tξ, we obtain ξ=(1t2)/t, η=1t2. The curve has a loop branching at the origin, which corresponds to the two values t=1 and t=1. Expressing the given function in terms of t, and making t tend to 1 or 1, we obtain the limiting values 32, 23.]

 

30. If f(x)=1sinxsina1(xa)cosa, then dda{limxaf(x)}limxaf(x)=34sec3a512seca.

 

31. Show that if ϕ(x)=1/(1+x2) then ϕn(x)=Qn(x)/(1+x2)n+1, where Qn(x) is a polynomial of degree n. Show also that

(i) Qn+1=(1+x2)Qn2(n+1)xQn,

(ii) Qn+2+2(n+2)xQn+1+(n+2)(n+1)(1+x2)Qn=0,

(iii) (1+x2)Qn2nxQn+n(n+1)Qn=0,

(iv) Qn=(1)nn!{(n+1)xn(n+1)n(n1)3!xn2+},

(v) all the roots of Qn=0 are real and separated by those of Qn1=0.

 

32. If f(x), ϕ(x), ψ(x) have derivatives when axb, then there is a value of ξ lying between a and b and such that |f(a)ϕ(a)ψ(a)f(b)ϕ(b)ψ(b)f(ξ)ϕ(ξ)ψ(ξ)|=0.

[Consider the function formed by replacing the constituents of the third row by f(x), ϕ(x), ψ(x). This theorem reduces to the Mean Value Theorem (§ 125) when ϕ(x)=x and ψ(x)=1.]

 

33. Deduce from Ex. 32 the formula f(b)f(a)ϕ(b)ϕ(a)=f(ξ)ϕ(ξ).

 

34. If ϕ(x)a as x, then ϕ(x)/xa. If ϕ(x) then ϕ(x). [Use the formula ϕ(x)ϕ(x0)=(xx0)ϕ(ξ), where x0<ξ<x.]

 

35. If ϕ(x)a as x, then ϕ(x) cannot tend to any limit other than zero.

 

36. If ϕ(x)+ϕ(x)a as x, then ϕ(x)a and ϕ(x)0.

[Let ϕ(x)=a+ψ(x), so that ψ(x)+ψ(x)0. If ψ(x) is of constant sign, say positive, for all sufficiently large values of x, then ψ(x) steadily increases and must tend to a limit l or to . If ψ(x) then ψ(x), which contradicts our hypothesis. If ψ(x)l then ψ(x)l, and this is impossible (Ex. 35) unless l=0. Similarly we may dispose of the case in which ψ(x) is ultimately negative. If ψ(x) changes sign for values of x which surpass all limit, then these are the maxima and minima of ψ(x). If x has a large value corresponding to a maximum or minimum of ψ(x), then ψ(x)+ψ(x) is small and ψ(x)=0, so that ψ(x) is small. A fortiori are the other values of ψ(x) small when x is large.

For generalisations of this theorem, and alternative lines of proof, see a paper by the author entitled “Generalisations of a limit theorem of Mr Mercer,” in volume 43 of the Quarterly Journal of Mathematics. The simple proof sketched above was suggested by Prof. E. W. Hobson.]

 

37. Show how to reduce R{x,ax+bmx+n,cx+dmx+n}dx to the integral of a rational function. [Put mx+n=1/t and use Ex. XLIX. 13.]

 

38. Calculate the integrals: dx(1+x2)3,x1x+1dxx,xdx1+x1+x3,a2+b2+cxdx,csc3xdx,5cosx+62cosx+sinx+3dx,dx(2sin2x)(2+sinxsin2x),cosxsinxdxcos4x+sin4x,cscxsec2xdx,dx(1+sinx)(2+sinx),x+sinx1+cosxdx,arcsecxdx,(arcsinx)2dx,xarcsinxdx,xarcsinx1x2dx,arcsinxx3dx,arcsinx(1+x)2dx,arctanxx2dx,arctanx(1+x2)3/2dx,log(α2+β2x2)x2dx,log(α+βx)(a+bx)2dx.

 

39. Formulae of reduction. (i) Show that 2(n1)(q14p2)dx(x2+px+q)n=x+12p(x2+px+q)n1+(2n3)dx(x2+px+q)n1.

[Put x+12p=t, q14p2=λ: then we obtain dt(t2+λ)n=1λdt(t2+λ)n11λt2dt(t2+λ)n=1λdt(t2+λ)n1+12λ(n1)tddt{1(t2+λ)n1}dt, and the result follows on integrating by parts.

A formula such as this is called a formula of reduction. It is most useful when n is a positive integer. We can then express dx(x2+px+q)n in terms of dx(x2+px+q)n1, and so evaluate the integral for every value of n in turn.]

(ii) Show that if Ip,q=xp(1+x)qdx then (p+1)Ip,q=xp+1(1+x)qqIp+1,q1, and obtain a similar formula connecting Ip,q with Ip1,q+1. Show also, by means of the substitution x=y/(1+y), that Ip,q=(1)p+1yp(1+y)pq2dy.

(iii) Show that if X=a+bx then xX1/3dx=3(3a2bx)X2/3/10b2,x2X1/3dx=3(9a26abx+5b2x2)X2/3/40b3,xX1/4dx=4(4a3bx)X3/4/21b2,x2X1/4dx=4(32a224abx+21b2x2)X3/4/231b3.

(iv) If Im,n=xmdx(1+x2)n then 2(n1)Im,n=xm1(1+x2)(n1)+(m1)Im2,n1.

(v) If In=xncosβxdx and Jn=xnsinβxdx then βIn=xnsinβxnJn1,βJn=xncosβx+nIn1.

(vi) If In=cosnxdx and Jn=sinnxdx then nIn=sinxcosn1x+(n1)In2,nJn=cosxsinn1x+(n1)Jn2.

(vii) If In=tannxdx then (n1)(In+In2)=tann1x.

(viii) If Im,n=cosmxsinnxdx then 2(m+n)Im,n=cosm+1xsinn1x+(n1)Im,n2=cosm1xsinn+1x+(m1)Im2,n.

[We have (m+1)Im,n=sinn1xddx(cosm+1x)dx=cosm+1xsinn1x+(n1)cosm+2xsinn2xdx=cosm+1xsinn1x+(n1)(Im,n2Im,n), which leads to the first reduction formula.]

(ix) Connect Im,n=sinmxsinnxdx with Im2,n.

(x) If Im,n=xmcscnxdx then (n1)(n2)Im,n=(n2)2Im,n2+m(m1)Im2,n2xm1cscn1x{msinx+(n2)xcosx}.

(xi) If In=(a+bcosx)ndx then (n1)(a2b2)In=bsinx(a+bcosx)(n1)+(2n3)aIn1(n2)In2.

(xii) If In=(acos2x+2hcosxsinx+bsin2x)ndx then 4n(n+1)(abh2)In+22n(2n+1)(a+b)In+1+4n2In=d2Indx2.

If Im,n=xm(logx)ndx then (m+1)Im,n=xm+1(logx)nnIm,n1.

 

40. If n is a positive integer then the value of xm(logx)ndx is xm+1{(logx)nm+1n(logx)n1(m+1)2+n(n1)(logx)n2(m+1)3+(1)nn!(m+1)n+1}.

 

41. Show that the most general function ϕ(x), such that ϕ+a2ϕ=0 for all values of x, may be expressed in either of the forms Acosax+Bsinax, ρcos(ax+ϵ), where A, B, ρ, ϵ are constants. [Multiplying by 2ϕ and integrating we obtain ϕ2+a2ϕ2=a2b2, where b is a constant, from which we deduce that ax=dϕb2ϕ2.]

 

42. Determine the most general functions y and z such that y+ωz=0, and zωy=0, where ω is a constant and dashes denote differentiation with respect to x.

 

43. The area of the curve given by x=cosϕ+sinαsinϕ1cos2αsin2ϕ,y=sinϕsinαcosϕ1cos2αsin2ϕ, where α is a positive acute angle, is 12π(1+sinα)2/sinα.

 

44. The projection of a chord of a circle of radius a on a diameter is of constant length 2acosβ; show that the locus of the middle point of the chord consists of two loops, and that the area of either is a2(βcosβsinβ).

 

45. Show that the length of a quadrant of the curve (x/a)2/3+(y/b)2/3=1 is (a2+ab+b2)/(a+b).

 

46. A point A is inside a circle of radius a, at a distance b from the centre. Show that the locus of the foot of the perpendicular drawn from A to a tangent to the circle encloses an area π(a2+12b2).

 

47. Prove that if (a,b,c,f,g,h|x,y,1)2=0 is the equation of a conic, then dx(lx+my+n)(hx+by+f)=αlogPTPT+β, where PT, PT are the perpendiculars from a point P of the conic on the tangents at the ends of the chord lx+my+n=0, and α, β are constants.

 

48. Show that ax2+2bx+c(Ax2+2Bx+C)2dx will be a rational function of x if and only if one or other of ACB2 and aC+cA2bB is zero.1

 

49. Show that the necessary and sufficient condition that f(x){F(x)}2dx, where f and F are polynomials of which the latter has no repeated factor, should be a rational function of x, is that fFfF should be divisible by F.

 

50. Show that αcosx+βsinx+γ(1ecosx)2dx is a rational function of cosx and sinx if and only if αe+γ=0; and determine the integral when this condition is satisfied.


  1. See the author’s tract quoted on § 131.↩︎

146. Lengths of plane curves Main Page Chapter VII