D. Transcendental Functions. We have already proved (Ex. XXXIX. 4) that Dxsinx=cosx,Dxcosx=sinx.

By means of Theorems (4) and (5) of § 113, the reader will easily verify that 2Dxtanx=sec2x,Dxcotx=csc2x,Dxsecx=tanxsecx,Dxcscx=cotxcscx. And by means of Theorem (7) we can determine the derivatives of the ordinary inverse trigonometrical functions. The reader should verify the following formulae: 2Dxarcsinx=±1/1x2,Dxarccosx=1/1x2,Dxarctanx=1/(1+x2),Dxarccotx=1/(1+x2),Dxarcsecx=±1/{xx21},Dxarccosecx=1/{xx21}. In the case of the inverse sine and cosecant the ambiguous sign is the same as that of cos(arcsinx), in the case of the inverse cosine and secant the same as that of sin(arccosx).

The more general formulae Dxarcsin(x/a)=±1/a2x2,Dxarctan(x/a)=a/(x2+a2), which are also easily derived from Theorem (7) of § 113, are also of considerable importance. In the first of them the ambiguous sign is the same as that of acos{arcsin(x/a)}, since a1(x2/a2)=±a2x2 according as a is positive or negative.

Finally, by means of Theorem (6) of § 113, we are enabled to differentiate composite functions involving symbols both of algebraical and trigonometrical functionality, and so to write down the derivative of any such function as occurs in the following examples.

Example XLIV

1. Find the derivatives of

cosmx,sinmx,cosxm,sinxm,cos(sinx),sin(cosx),a2cos2x+b2sin2x,cosxsinxa2cos2x+b2sin2x,xarcsinx+1x2,(1+x)arctanxx.

2. Verify by differentiation that arcsinx+arccosx is constant for all values of x between 0 and 1, and arctanx+arccotx for all positive values of x.

3. Find the derivatives of arcsin1x2,arcsin{2x1x2},arctan(a+x1ax). How do you explain the simplicity of the results?

4. Differentiate 1acb2arctanax+bacb2,1aarcsinax+bb2ac.

5. Show that each of the functions 2arcsinxβαβ,2arctanxβαx,arcsin2(αx)(xβ)αβ has the derivative 1(αx)(xβ).

6. Prove that ddθ{arccoscos3θcos3θ}=3cosθcos3θ.

7. Show that 1C(AcaC)ddx[arccosC(ax2+c)c(Ax2+C)]=1(Ax2+C)ax2+c.

8. Each of the functions 1a2b2arccos(acosx+ba+bcosx),2a2b2arctan{aba+btan12x} has the derivative 1/(a+bcosx).

9. If X=a+bcosx+csinx, and y=1a2b2c2arccosaXa2+b2+c2Xb2+c2, then dy/dx=1/X.

10. Prove that the derivative of F[f{ϕ(x)}] is F[f{ϕ(x)}]f{ϕ(x)}ϕ(x), and extend the result to still more complicated cases.

11. If u and v are functions of x, then Dxarctan(u/v)=(vDxuuDxv)/(u2+v2).

12. The derivative of y=(tanx+secx)m is mysecx.

13. The derivative of y=cosx+isinx is iy.

14. Differentiate xcosx, (sinx)/x. Show that the values of x for which the tangents to the curves y=xcosx, y=(sinx)/x are parallel to the axis of x are roots of cotx=x, tanx=x respectively.

15. It is easy to see (cf. EX. XVII. 5) that the equation sinx=ax, where a is positive, has no real roots except x=0 if a1, and if a<1 a finite number of roots which increases as a diminishes. Prove that the values of a for which the number of roots changes are the values of cosξ, where ξ is a positive root of the equation tanξ=ξ. [The values required are the values of a for which y=ax touches y=sinx.]

16. If ϕ(x)=x2sin(1/x) when x0, and ϕ(0)=0, then ϕ(x)=2xsin(1/x)cos(1/x) when x0, and ϕ(0)=0. And ϕ(x) is discontinuous for x=0 (cf. § 111, (2)).

17. Find the equations of the tangent and normal at the point (x0,y0) of the circle x2+y2=a2.

[Here y=a2x2, dy/dx=x/a2x2, and the tangent is yy0=(xx0){x0/a2x02}, which may be reduced to the form xx0+yy0=a2. The normal is xy0yx0=0, which of course passes through the origin.]

18. Find the equations of the tangent and normal at any point of the ellipse (x/a)2+(y/b)2=1 and the hyperbola (x/a)2(y/b)2=1.

19. The equations of the tangent and normal to the curve x=ϕ(t), y=ψ(t), at the point whose parameter is t, are xϕ(t)ϕ(t)=yψ(t)ψ(t),{xϕ(t)}ϕ(t)+{yψ(t)}ψ(t)=0.


118. Differentiation of algebraical functions Main Page 120. Repeated differentiation