Periodicity of Trigonometric Functions
All trigonometric functions are defined in terms of the cosine and sine functions. The cosine and sine functions are characterized as the $x$ and $y$ coordinates of the intersection point $P$ of the terminal side of the angle $\theta$ and the unit circle (Figure 1).
Figure 1 
Because one revolution corresponds to $2\pi$ radians or 360 degrees, the same point $P$ is obtained for $\theta+2\pi k$ where $k$ is an integer. Thus the values of the trigonometric functions repeat when $\theta$ increases by $2\pi$. The sine and cosine functions are periodic with period $2\pi$ \[ \sin(\theta+2\pi)=\sin\theta,\qquad\cos(\theta+2\pi)=\cos\theta \] but the tangent and cotangent functions have a smaller period $\pi$, because (see Equation 18(c) in Trignometric Identities) \[ \tan(\theta+\pi)=\tan\theta,\qquad\cot(\theta+\pi)=\cot\theta. \]
We may use the periodicity of trigonometric functions to sketch their graphs. So we can just sketch the graphs of sine and cosine functions for $\theta$ between $0$ and $2\pi$ (or for $\theta$ between $\pi$ and $\pi$ or in general for $\theta$ between $a$ and $a+2\pi$ for any real number $a$) and then obtain the graph for all real values of $\theta$ by infinitely many repetitions of this cycle, to the right and to the left.
Graph of y = sin ????
To sketch the graph of $\sin\theta$, we just need to look at Figure 2 and follow how the $y$ coordinate of the point $P$ varies as $\theta$ increases from $0$ to $2\pi$ and $P$ completes one counterclockwise revolution. We know $\sin0=0$. As $\theta$ goes from $0$ to $\pi/2$, $\sin\theta$ increases until it reaches $+1$ at $\theta=\pi/2$. As $\theta$ goes from $\pi/2$ to $\pi$, $\sin\theta$ decreases until reaches $0$ at $\theta=\pi$. When $\theta$ is between $\pi$ to $3\pi/2$, $\sin\theta$ is negative and keep decreasing until it reaches $1$ at $\theta=3\pi/2$. Finally as $\theta$ goes from $3\pi/2$ to $2\pi$, $\sin\theta$ increases from $1$ to $0$ and will be ready to start all over again.
Figure 2: Graph of $y=\sin\theta$ in one period 
The complete graph $y=\sin\theta$ consists of infinitely many repetitions of one cycle just shown (Figure 3).
Figure 3: Graph of $y=\sin\theta$. Domain$=(\infty,\infty)$, range $=[1,1]$, period$=2\pi$ 

Note that $y=\sin\theta$ is an odd function (that is, $\sin(\theta)=\sin\theta),$and thus its graph is symmetric about the origin.
Graph of y = cos ????
We can graph $y=\cos\theta$ essentially the same way. The main difference is $\cos0=1$ and $\cos\theta$ decreases until it becomes $\cos\frac{\pi}{2}=0$ and finally it reaches $1$ at $\theta=\pi$. At this point, $\cos\theta$ starts to increase until it becomes $\cos\frac{3\pi}{2}=0$ and then $\cos2\pi=1$ (Figure 4(a)), and it will start all over again (Figure 4(b)).
(a)  (b)Domain $=(\infty,\infty)$, range$=[1,1]$, period$=2\pi$ 
Figure 4: Graph of $y=\cos\theta$ (a) in one cycle (b) in several cycles
Another way of drawing the graph of $y=\cos\theta$ is by shifting the graph of $y=\sin\theta$ to the left $\pi/2$ units (Figure 5) because $\cos\theta=\sin\left(\theta+\frac{\pi}{2}\right)$ (see Equation 17(a) in Trigonometric Identites). As we can see in Figure 5:
 The sine and cosine functions are defined for all values of $\theta$ and their range is $\{y1\leq y\leq1\}=[1,1]$.
 The sine function takes on 0 at $x=0,\pm\pi,\pm2\pi,\pm3\pi,\cdots$.
 The cosine function takes on 0 at $x=\pm\frac{\pi}{2},\pm\frac{3\pi}{2},\pm\frac{5\pi}{2},\pm\frac{7\pi}{2},\cdots$
Figure 5: Graph of $y=\cos\theta$ is obtained by shifting the graph of $y=\sin\theta$ to the left $\pi/2$ units. 
Note that $y=\cos\theta$ is an even function (that is, $\cos(\theta)=\cos\theta)$, and thus its graph is symmetric about the $y$axis.
Graph of y = tan ????
Now let’s sketch the graph of $y=\tan\theta$. We discussed that the period of this function is $\pi$, so we can plot it in one period and find the complete graph by repeating what we obtain in one interval. For example, we can take the interval \[ \frac{\pi}{2}<\theta<\frac{\pi}{2}. \] Note that $\tan\theta=\sin\theta/\cos\theta$ is not defined for $\theta=\pm\pi/2$ because because $\cos(\pm\pi/2)=0$ and division by zero is not defined. We know $\tan0=0$. When $\frac{\pi}{2}<\theta<0$ (that is when $\theta$ is in the fourth quadrant), $\tan\theta<0$ and when $0<\theta<\frac{\pi}{2}$, $\tan\theta>0$. As $\theta$ increases toward $\pi/2$, $\tan\theta$ is positive and becomes indefinitely great, while as $\theta$ decreases toward $\frac{\pi}{2},$ $\tan\theta$ is negative and becomes indefinitely great. You can also see this in Figure 6(a).
 The domain of $y=\tan\theta$ is the set of all $\theta$values such that \[\theta\neq(2k+1)\frac{\pi}{2},\quad k\text{ is an integer.}\]
 As we can see in Figure 6, the range of $y=\tan\theta$ is the entire set of real numbers $\mathbb{R}$ or $(\infty,\infty)$.
 To graph trigonometric functions in the coordinate plane, as usual, we often denote the independent variable by $x$. So we often talk about the graphs of $y=\sin x,y=\cos x$, $y=\tan x$, etc.
(a)  (b) Domain $=\{\theta\ \theta\neq(2k+1)\frac{\pi}{2},\ k\in\mathbb{Z}\}$ 
Figure 6: (a) Graph of $y=\tan\theta$ in one period $\frac{\pi}{2}<\theta<\frac{\pi}{2}$. (b) The complete graph of $y=\tan\theta$.